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familytree a) self.person = self.marriage.child marriage b) self.child.birthfam = self c) self.husband.birthdate < self.wife.birthdate person d) self.birthfam.child_include(self) e) self.marriage->size = 1 f) self.marriage.wife.birthdate < self.birthdate 3. Write OCL constraints for a restaurant without a smoking section that seats customers in order of arrival. Class group Char* name Int number Int arrivalorder Class waitlist Group* list[MAX] Int listptr Void addtolist(group* newgroup) Group* seatnext() Class restaurant Waitlist* waiting Void arrive(group* newgroup) Group* seat()

we accept the hypothesis that the median is 66 at the 0.05 level. Note that we could also have used 15, the number of minus signs. In this case z with the same conclusion. (b) Subtracting 75 from all the entries in Table 10-5 gives us Table 10-7, in which there are 13 pluses and 27 minuses. Since z (13 0.5) (40)(0.5) !(40)(0.5)(0.5) 2.06 (15 0.5) (38)(0.5) !(38)(0.5)(0.5) 1.14

Fig. 5-32

we reject the hypothesis that the median is 75 at the 0.05 level. Table 10-7

Using this method, we can arrive at a 95% confidence interval for the median grade on the examination. (see Problem 10.30.)

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Therefore, vo:c: 5 19:8 99 V is:c: 99=3 33 A The Thevenin equivalent is shown in Fig. 5-32. (b) With the load Rl connected, we have v2 Rl 99Rl v Rl RTh Th Rl 3 and p v2 2 Rl vTh vo:c: 99 V RTh vo:c: =is:c: 3

The Mann Whitney U test 10.5. Referring to Table 10-2, determine whether there is a difference at the 0.05 significance level between cables made of alloy I and alloy II.

Table 5-3 shows the voltage across the load and the power dissipated in it for the given seven values of Rl . The load voltage is at its maximum when Rl 1. However, power delivered to Rl 1 is zero. Power delivered to Rl is maximum at Rl 3

We organize the work in accordance with steps 1, 2, and 3 (described earlier in this chapter):

1. What kind of questions are speci cations supposed to be able to answer Usually, the questions are about the behavior of the proposed software. Developers should be able to use the speci cations to determine exactly what the software should do in a speci ed situation. 2. Why would ambiguity be a problem If the ambiguity means that the developer will interpret the speci cation di erently than what the user wants, then there will be a problem. 3. Why are mathematical notions, such as sets, a good foundation for speci cations Mathematical notions such as sets are a good foundation for speci cations because sets and set operations are precisely de ned. For example, the union of two sets is well understood. If the behavior of a function can be de ned as operations on speci ed sets, then it will be easy to determine exactly what the function is supposed to do. 4. What is the di erence between preconditions, post-conditions, and invariants A precondition is something that has to be true before a function can execute. A postcondition is something that has to be true on completion of the function. An invariant is something that should be true throughout the execution of the function. Actually, most invariants are true between every operation.

Step 1. Combining all 18 sample values in an array from the smallest to the largest gives us the first line of Table 10-8. These values are numbered 1 to 18 in the second line, which gives us the ranks. Step 2. To find the sum of the ranks for each sample, rewrite Table 10-2 by using the associated ranks from Table 10-8; this gives us Table 10-9. The sum of the ranks is 106 for alloy I and 65 for alloy II.

, which is equal to the output resistance of the ampli er. Table 5-3 Rl ;

Table 10-8

0.5 1 3 5 10 100 1000 v2 ; V 14.14 24.75 49.50 61.88 76.15 96.12 98.70 p; W 400.04 612.56 816.75 765.70 579.94 92.38 9.74

10.7 11.8 12.6 12.9 14.1 14.7 15.2 15.9 16.1 16.4 17.8 18.3 18.9 19.6 20.5 22.7 24.2 25.3 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

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